document.write( "Question 979810: Would someone please clarify my math on this?\r
\n" ); document.write( "\n" ); document.write( "The quadratic equation came out to: 4+/- 2 times radical 10, all divided by 4.\r
\n" ); document.write( "\n" ); document.write( "To solve, I divided each term in the numerator by 4, yielding 1 +/- radical 10 divided by 2.\r
\n" ); document.write( "\n" ); document.write( "However, the solution factored the 4 in the numerator and denominator, then canceled out three 2s to yield 2 +/- radical 10, all divided by 2. \r
\n" ); document.write( "\n" ); document.write( "They both calculate out to the same thing. But, so that I don't make future mistakes, it seems that either the solution didn't go all the way, or I did something that may have worked here, but is in fact wrong and may not work in the future.\r
\n" ); document.write( "\n" ); document.write( "Thanks for your thoughts.\r
\n" ); document.write( "\n" ); document.write( "Helen\r
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Algebra.Com's Answer #601053 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
4+/- 2 times radical 10, all divided by 4.
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document.write( "\"%284+%2B-+2sqrt%2810%29%29%2F4\"\r\n" );
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document.write( "You can either do as you did and make two fractions:\r\n" );
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document.write( "\"4%2F4+%2B-+2sqrt%2810%29%2F4\"\r\n" );
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document.write( "The simplify as\r\n" );
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document.write( "\"1+%2B-+sqrt%2810%2F2%29\"\r\n" );
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document.write( "Or else you can factor 2 out of the numerator:\r\n" );
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document.write( "\"%282%282+%2B-+sqrt%2810%29%29%29%2F4\"\r\n" );
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document.write( "Then divide numerator and denominator by 2\r\n" );
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document.write( "\"%282+%2B-+sqrt%2810%29%29%2F2\"\r\n" );
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document.write( "They are both correct and equal.\r\n" );
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document.write( "It's very similar to the question of whether we \r\n" );
document.write( "prefer \"3%2F2\" to \"1%261%2F2\".  Your teacher could not \r\n" );
document.write( "mark either one wrong.\r\n" );
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document.write( "Edwin
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