document.write( "Question 979693: (This problem is about the sum and product of roots of quadratic equations)\r
\n" ); document.write( "\n" ); document.write( "For what value of p does the sum of roots of the equation 6x^2-3px+5=0 equal the product of roots?
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Algebra.Com's Answer #601019 by ikleyn(52778)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "You are given an equation\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2-3px%2B5\" = \"0\". \r
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\n" ); document.write( "\n" ); document.write( "Apply the  Viete's theorem  (see the lesson  Solving quadratic equations without quadratic formula  in this site):\r
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\n" ); document.write( "\n" ); document.write( "According to this theorem, \r
\n" ); document.write( "\n" ); document.write( "    a)  the sum of the roots of the quadratic equation is equal to the coefficient at  x  taken with the opposite sign and divided by the coefficient at \"x%5E2\":\r
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\n" ); document.write( "\n" ); document.write( "          \"x%5B1%5D\" + \"x%5B2%5D\" = \"3p%2F6\" = \"p%2F2\". \r
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\n" ); document.write( "\n" ); document.write( "    b)  the sum of the roots is equal to the constant term divided by the coefficient at \"x%5E2\":\r
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\n" ); document.write( "\n" ); document.write( "          \"x%5B1%5D\".\"x%5B2%5D\" = \"5%2F6\".\r
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\n" ); document.write( "\n" ); document.write( "Now,  the condition of the problem requires that \r
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\n" ); document.write( "\n" ); document.write( "\"x%5B1%5D\" + \"x%5B2%5D\" = \"x%5B1%5D\".\"x%5B2%5D\",\r
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\n" ); document.write( "\n" ); document.write( "which implies that \r
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\n" ); document.write( "\n" ); document.write( "\"p%2F2\" = \"5%2F6\". \r
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\n" ); document.write( "\n" ); document.write( "Hence,  p = \"2%2A%285%2F6%29\" = \"5%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "As a last step,  substitute this value of  p  into the original equation,  find its roots and make sure that the roots satisfy to the imposed condition. \r
\n" ); document.write( "\n" ); document.write( "Please,   do it yourself.     Good luck! \r
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