document.write( "Question 979701: If \"+x+=++sqrt%28+pq+%29+\" and \"+y+=+expr%281%2F2%29+%28p%2Bq%29+\" prove that x < y \n" ); document.write( "
Algebra.Com's Answer #600996 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Note:  It must be stated that \r\n" );
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document.write( "p ≧ 0, q ≧ 0, pq > 0, p ≠ q, \r\n" );
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document.write( "otherwise the inequality is false.  I'll assume these,\r\n" );
document.write( "but first I'll give two examples to show you that this \r\n" );
document.write( "is false without those assumptions.\r\n" );
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document.write( "It isn't true when p=-8, q=-2 because\r\n" );
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document.write( "\"x=sqrt%28p%2Aq%29=sqrt%28%28-8%29%28-2%29%29=+sqrt%2816%29+=+4\"\r\n" );
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document.write( "Yet 4 < -5 is false.\r\n" );
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document.write( "It also isn't true when p=1, q=1 because\r\n" );
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document.write( "\"x=sqrt%28p%2Aq%29=sqrt%28%281%29%281%29%29=+sqrt%281%29+=+1\"\r\n" );
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document.write( "Yet 1 < 1 is false.\r\n" );
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document.write( "It must be stated that p ≧ 0, q ≧ 0, pq > 0, p ≠ q,\r\n" );
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document.write( "It is also easy to see that it is true if p is 0 and q isn't \r\n" );
document.write( "or if q is 0 and p isn't, but they both cannot be 0.\r\n" );
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document.write( "-------------------------------------------\r\n" );
document.write( "Here is the proof\r\n" );
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document.write( "\"p+%26%238800%3B+q\"  assumed as given\r\n" );
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document.write( "\"p-q+%26%238800%3B+0\"\r\n" );
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document.write( "The square of any non-zero number is positive, so\r\n" );
document.write( "we can square both sides:\r\n" );
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document.write( "\"%28p-q%29%5E2+%3E+0%5E2\"\r\n" );
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document.write( "\"p%5E2-2pq%2Bq%5E2+%3E+0\"\r\n" );
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document.write( "add 4pq to both sides:\r\n" );
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document.write( "\"p%B2%2B2pq%2Bq%B2+%3E+4pq\"\r\n" );
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document.write( "Factor the left side\r\n" );
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document.write( "\"%28p%2Bq%29%28p%2Bq%29+%3E+4pq\"\r\n" );
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document.write( "Write left side as the square of a binomial:\r\n" );
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document.write( "\"%28p%2Bq%29%B2+%3E+4pq\"\r\n" );
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document.write( "Take non-negative square roots of both sides \r\n" );
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document.write( "\"sqrt%28%28p%2Bq%29%5E2%29+%3E+sqrt%284pq%29\"\r\n" );
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document.write( "\"p%2Bq+%3E+2sqrt%28pq%29\"\r\n" );
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document.write( "Multiply both sides by 1/2:\r\n" );
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document.write( "\"expr%281%2F2%29%28p%2Bq%29+%3E+sqrt%28pq%29\"\r\n" );
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document.write( "\"y+%3E+x\"\r\n" );
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document.write( "Same as \r\n" );
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document.write( "\"x+%3C+y\"\r\n" );
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document.write( "Edwin

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