document.write( "Question 979663: The cost C of a pound of a margarine in 2006 was 66 cents. in 2010 the cost was 83 cents. assuming the exponential growth model applies:\r
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document.write( "A: Find the exponential growth rate to the nearest tenth of a percent, and write the equation.\r
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document.write( "B: Find the cost of a pound of margarine in 2012 and 2018 \n" );
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Algebra.Com's Answer #600957 by josgarithmetic(39625) ![]() You can put this solution on YOUR website! You may have a choice of \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Which form of the model? Your choice.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This help posting will use the first one. \n" ); document.write( "EITHER base you like, find logarithm of both sides. I will use natural log base just for convenience. You use base ten, if you want.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The points to use for this linear form need to use natural log of the costs, because the linear equation defines a formula for the natural log of cost.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The ordered pairs for your points are (2006, ln(66)) and (2010, ln(83)).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You already have learned what to do with a system of two linear equations. Using each pair of points gives a corresponding equation, and the new unknowns to solve for will be |