document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979649>Question 979649</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a club consists of 16 members, how many different arrangements of<BR>\n" );
document.write( "President vice president , and secretary are possible?i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600942 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is 16C3, since order does not matter.<BR>\n" );
document.write( "That can be done on a calculator OR<BR>\n" );
document.write( "16!/3!13!= 16*15*14*13!/13!*6, since 3!=6.\r<BR>\n" );
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document.write( "That is 16*15*14/6=560 ways. </SPAN>\n" );
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