document.write( "Question 83568: Three years back the age of a father was 24 years more than his son. At present the father is 5 times as old as the son. How old will the son be three years from now? \n" ); document.write( "
Algebra.Com's Answer #60094 by ankor@dixie-net.com(22740)\"\" \"About 
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Three years back the age of a father was 24 years more than his son. At present the father is 5 times as old as the son. How old will the son be three years from now?
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\n" ); document.write( "Actually the Father will always be 24 yrs older than his son, 3 years ago or anytime. but here is a method,
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\n" ); document.write( "Let F = father's age now; S = son's age now
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\n" ); document.write( "Three years ago:
\n" ); document.write( "father: (F-3)
\n" ); document.write( "son: (S-3)
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\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( "\"Three years back the age of a father was 24 years more than his son.\"
\n" ); document.write( "(F-3) = (S-3) + 24
\n" ); document.write( "Simplify
\n" ); document.write( "F - 3 = S - 3 + 24
\n" ); document.write( "F - 3 = S + 21
\n" ); document.write( "F = S + 21 + 3
\n" ); document.write( "F = S + 24; use for substitution in the next equation
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\n" ); document.write( "\"At present the father is 5 times as old as the son.\"
\n" ); document.write( "F = 5S
\n" ); document.write( "Substitute (S+24) for F
\n" ); document.write( "S + 24 = 5S
\n" ); document.write( "24 = 5S - S
\n" ); document.write( "24 = 4S
\n" ); document.write( "S = 24/4
\n" ); document.write( "S = 6 yrs old now
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\n" ); document.write( " How old will the son be three years from now?
\n" ); document.write( "Son: 6 + 3 = 9 yrs old
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\n" ); document.write( "Check: (Father's age now is 30)
\n" ); document.write( "At present the father is 5 times as old as the son.
\n" ); document.write( "5*6 = 30
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\n" ); document.write( "Hope this made sense to you on this fine Memorial Day!
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