document.write( "Question 83569: find area of a ideal triangle 3x4x5 \n" ); document.write( "
Algebra.Com's Answer #60093 by Edwin McCravy(20086)\"\" \"About 
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document.write( "find area of a ideal triangle 3x4x5\r\n" );
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document.write( "The formula for the area of a triangle is \r\n" );
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document.write( "     \"A\" = \"1%2F2\"base×altitude\r\n" );
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document.write( "A 3-4-5 triangle is a right triangle because it\r\n" );
document.write( "satisfies the Pythagorean theorem:\r\n" );
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document.write( "a˛ + b˛ = c˛\r\n" );
document.write( "3˛ + 4˛ = 5˛\r\n" );
document.write( " 9 + 16 = 25\r\n" );
document.write( "     25 = 25\r\n" );
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document.write( "  \r\n" );
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document.write( "So the base is b which is 3, and the altitude is a which is 4.\r\n" );
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document.write( "Substituting into the formula for the area:\r\n" );
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document.write( "        A = \"1%2F2\"×base×altitude\r\n" );
document.write( "        A = \"1%2F2\"×3×4\r\n" );
document.write( "        A = \"1%2F2\"×12\r\n" );
document.write( "        A = 6 square units\r\n" );
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document.write( "Edwn
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