document.write( "Question 979620:  An experiment is carried out in which the number n of bacteria in a liquid, is given by the formula , where t is the time in minutes after the beginning of the experiment and k is a constant. The number of bacteria doubles every 20 minutes. Find the exact value of k. \n" );
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| Algebra.Com's Answer #600912 by Cromlix(4381)     You can put this solution on YOUR website! Hi there, \n" ); document.write( "n = 650e^kt \n" ); document.write( "The current value for the bacteria = 650 \n" ); document.write( "If the number doubles then n = 1300 \n" ); document.write( "So n = 650e^kt \n" ); document.write( "=> 1300 = 650e^20k \n" ); document.write( "=> 1300/650 = e^20k \n" ); document.write( "=> 2 = e^20k \n" ); document.write( "=> log(base e)2 = 20k log(base e) e \n" ); document.write( "log(base e)e = 1 \n" ); document.write( "=> log(base e)2 = 20k \n" ); document.write( "=> k = log(base e)2/20 \n" ); document.write( "=> k = 0.03466 (to 5 decimal places) \n" ); document.write( "Hope this helps:-) \n" ); document.write( " |