document.write( "Question 979620: An experiment is carried out in which the number n of bacteria in a liquid, is given by the formula \"n=650e%5E%28kt%29\", where t is the time in minutes after the beginning of the experiment and k is a constant. The number of bacteria doubles every 20 minutes. Find the exact value of k. \n" ); document.write( "
Algebra.Com's Answer #600912 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "n = 650e^kt
\n" ); document.write( "The current value for the bacteria = 650
\n" ); document.write( "If the number doubles then n = 1300
\n" ); document.write( "So n = 650e^kt
\n" ); document.write( "=> 1300 = 650e^20k
\n" ); document.write( "=> 1300/650 = e^20k
\n" ); document.write( "=> 2 = e^20k
\n" ); document.write( "=> log(base e)2 = 20k log(base e) e
\n" ); document.write( "log(base e)e = 1
\n" ); document.write( "=> log(base e)2 = 20k
\n" ); document.write( "=> k = log(base e)2/20
\n" ); document.write( "=> k = 0.03466 (to 5 decimal places)
\n" ); document.write( "Hope this helps:-)
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