document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972301>Question 972301</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a length of 38 yards less than 9 times its width. If the area of the rectangle is 5992 spare yards. Find the length of the rectangle  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600911 by </B><A HREF=/tutors/aboutme.mpl?userid=Timnewman><B>Timnewman(323)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Timnewman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Timnewman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width of the rectngle<BR>\n" );
document.write( "be w<BR>\n" );
document.write( "lenght L=9w-38 ----(1)<BR>\n" );
document.write( "Are of the a rectangle=L*W<BR>\n" );
document.write( " therefore,<BR>\n" );
document.write( "       LW=5992 ---(2)<BR>\n" );
document.write( " From (1)<BR>\n" );
document.write( "     L=9w-38<BR>\n" );
document.write( "  w=(L+38)/9 ----(3)<BR>\n" );
document.write( "substitute for w in (2) using(3)<BR>\n" );
document.write( "  L(L+38)/9=5992<BR>\n" );
document.write( "(Lē+38L)/9=5992<BR>\n" );
document.write( "Lē+38L=53928<BR>\n" );
document.write( "then,<BR>\n" );
document.write( "Lē+38L-53892=0<BR>\n" );
document.write( "solving the quadratic equation,<BR>\n" );
document.write( "L=309.3yerds </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );