document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979595>Question 979595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to find the amplitude, period, phase shift, and midline of the following problem:\r<BR>\n" );
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document.write( "y=2sin&#952;-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600883 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> amplitude is 2, the distance above the mean.  The sine may vary between -1 and +1<BR>\n" );
document.write( "The period is 2 pi, because theta can vary between 0 and 2 pi,  If it were sin 2theta, then the period would be compressed.<BR>\n" );
document.write( "It is shifted down to y=-2, so the function has a range between -4 and 0.<BR>\n" );
document.write( "This is a sine function that begins 2 units below the origin, reaches 0 at pi over 2, -2 at pi, and -4 at 3pi/2, before returning to -2 at 2 pi<BR>\n" );
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