document.write( "Question 83543: write the equatio of the line with slope -2 and y-intercept (0,0). Then the graph the line.\r
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\n" ); document.write( "\n" ); document.write( "Solve the following system of linear inequalities by graphing.
\n" ); document.write( "3x+4y<12
\n" ); document.write( "X+3y<6
\n" ); document.write( "x>0
\n" ); document.write( "y>0 \n" ); document.write( "
Algebra.Com's Answer #60082 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
write the equation of the line with slope -2 and y-intercept (0,0).
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\n" ); document.write( "It's just y = -2x
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\n" ); document.write( "If you use the point/slope equation: y - 0 = -2(x - 0), y = -2x
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\n" ); document.write( "Then the graph the line.
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-2x%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Solve the following system of linear inequalities by graphing.
\n" ); document.write( "3x+4y<12
\n" ); document.write( "4y < -3x + 12
\n" ); document.write( "y < (-3/4)x + 12/4
\n" ); document.write( "y < (-3/4)x + 3; plot this graph from x = 0 to x = +6
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\n" ); document.write( "x + 3y < 6
\n" ); document.write( "3y < -x + 6
\n" ); document.write( "y < (-1/3)x + 6/3
\n" ); document.write( "y < (-1/3)x + 2; plot this graph from x = 0 to x = +6
\n" ); document.write( "x>0
\n" ); document.write( "y>0
\n" ); document.write( "It should look like this
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-2%2C+6%2C+-2%2C+6%2C+%28-3%2F4%29x%2B3%2C+%28-1%2F3%29x%2B2%29+\"
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\n" ); document.write( "The area of feasibility is below the lowest line, but positive x & y
\n" ); document.write( "The corners of this area are: 0,0; 4,0; 0,2; and at the intersection 2.4, 1.2
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