document.write( "Question 979260: Janene and Emily plan to go on a marathon training run. Emily arrives late, so Janene starts running 16 minute before Emily. Janene runs at an average rate of 9 minutes per mile, and Emily runs at an average rate of 8 1/4 minute per mile. Assuming that both girls started at the same location and ran the same route, how many minutes will Emily take to catch up to Janene? \n" ); document.write( "
Algebra.Com's Answer #600817 by ankor@dixie-net.com(22740)\"\" \"About 
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Janene starts running 16 minute before Emily.
\n" ); document.write( " Janene runs at an average rate of 9 minutes per mile, and Emily runs at an average rate of 8 1/4 minute per mile.
\n" ); document.write( " Assuming that both girls started at the same location and ran the same route, how many minutes will Emily take to catch up to Janene?
\n" ); document.write( ":
\n" ); document.write( "Let t = time for E to catch J
\n" ); document.write( "then
\n" ); document.write( "(t+16) = running time for J when she is caught
\n" ); document.write( ":
\n" ); document.write( "The reciprocal allows us the change their speed to mi per min
\n" ); document.write( "1/9 mi/min is J's speed
\n" ); document.write( "1/8.25 mi/min is E's speed
\n" ); document.write( ":
\n" ); document.write( "When E catches J, they will have ran the same distance
\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "\"1%2F8.25\"(t) = \"1%2F9\"(t+16)
\n" ); document.write( "multiply both sides by the product of 8.25 & 9, results:
\n" ); document.write( "9t = 8.25(t+16)
\n" ); document.write( "9t = 8.25t + 132
\n" ); document.write( "9t - 8.25t = 132
\n" ); document.write( ".75t = 132
\n" ); document.write( "t = 132/.75
\n" ); document.write( "t = 176 minutes for E to Catch J
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the actual distances they ran, should be the same
\n" ); document.write( "J ran 16 + 176 = 192 min
\n" ); document.write( "192 * \"1%2F9\" = 21\"1%2F3\" mi
\n" ); document.write( "176 * \"1%2F8.25\" = 21\"1%2F3\" mi
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