document.write( "Question 979513: Steve and Jordan are riding bikes. Jordan is riding at 7 mph and Steve is riding at 6 mph. If Jordan is 5 miles behind Steve, how long will it take for Jordan to catch up to Steve? \r
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Algebra.Com's Answer #600794 by Boreal(15235)\"\" \"About 
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Simple approach: He is 5 miles behind and gaining a 1 mile per hour. It will take 5 hours.\r
\n" ); document.write( "\n" ); document.write( "Complex approach:
\n" ); document.write( "Jordan is at point 0, Steve at point 5.\r
\n" ); document.write( "\n" ); document.write( "Steve's distance needs to equal Jordan's distance.
\n" ); document.write( "Steve is 5+6mph*x hours or 5+6x.
\n" ); document.write( "Jordan's distance is 7mph or 7x. The x works because they will be riding for the same time.\r
\n" ); document.write( "\n" ); document.write( "5+6x=7x
\n" ); document.write( "5=x
\n" ); document.write( "In 5 hours, Steve will travel 30 miles, and he will be 35 miles away from point 0.
\n" ); document.write( "In 5 hours, Jordan will travel 35 miles.
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