document.write( "Question 979470: triangle ABC is a right isosceles tri. with rt.angle at C.CD||AB &BD=BA.Find the angle DBC.? \n" ); document.write( "
Algebra.Com's Answer #600752 by Fombitz(32388)\"\" \"About 
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\n" ); document.write( "If \"AC=BC=x\", then
\n" ); document.write( "\"AB=BD=sqrt%282%29x\"
\n" ); document.write( "\"BCD=45\"
\n" ); document.write( "Then use the law of sines,
\n" ); document.write( "\"sin%28BDC%29%2F%28sqrt%282%29x%29=sin%2845%29%2Fx\"
\n" ); document.write( "\"sin%28BDC%29=%28sqrt%282%29%2F2%29%2F%28sqrt%282%29%29\"
\n" ); document.write( "\"sin%28BDC%29=1%2F2\"
\n" ); document.write( "\"BDC=30\"
\n" ); document.write( "Then,
\n" ); document.write( "\"BDC%2BDCB%2BDBC=180\"
\n" ); document.write( "\"30%2B45%2BDBC=180\"
\n" ); document.write( "\"DBC=180-75\"
\n" ); document.write( "\"DBC=105\"\r
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