document.write( "Question 979439: Multiplication of algebraic expression \r
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Algebra.Com's Answer #600744 by Edwin McCravy(20060) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "You can do it like you have to when the things you're\r\n" );
document.write( "multiplying aren't similar. \r\n" );
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document.write( "Use the formula\r\n" );
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document.write( "(A+B+C)(D+E+F) = AD+AE+AF+BD+BE+BF+CD+CE+CF\r\n" );
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document.write( "with \r\n" );
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document.write( "A=2x^2\r\n" );
document.write( "B=-3x\r\n" );
document.write( "C=1\r\n" );
document.write( "D=2x^2\r\n" );
document.write( "E=3x\r\n" );
document.write( "F=-1\r\n" );
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document.write( "AD = (2x^2)(2x^2) = 4x^4\r\n" );
document.write( "AE = (2x^2)(3x) = 6x^3\r\n" );
document.write( "AF = (2x^2)(-1) = -2x^2\r\n" );
document.write( "BD = (-3x)(2x^2) = -6x^3\r\n" );
document.write( "BE = (-3x)(3x) = -9x^2\r\n" );
document.write( "BF = (-3x)(-1) = 3x\r\n" );
document.write( "CD = (1)(2x^2) = 2x^2\r\n" );
document.write( "CE = (1)(3x) = 3x\r\n" );
document.write( "CF = (1)(-1) = -1\r\n" );
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document.write( "4x^4+6x^3-2x^2-6x^3-9x^2+3x+2x^2+3x-1\r\n" );
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document.write( "Combine like terms and end up with\r\n" );
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document.write( "4x^4-9x^2+6x-1\r\n" );
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document.write( "But since the two factors are similar you can make them\r\n" );
document.write( "become conjugates and it's a good bit easier to do it this way\r\n" );
document.write( "when you can:\r\n" );
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document.write( "Factor -1 out of the last two terms in the first parentheses.\r\n" );
document.write( "Factor +1 out of the last two terms in the second parentheses.\r\n" );
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document.write( "Now they are conjugates.\r\n" );
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document.write( "So when you FOIL that out the OUTER product and the INNER\r\n" );
document.write( "product cancel and you get:\r\n" );
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document.write( "To square the last binomial multiply it by itself\r\n" );
document.write( "and use FOIL:\r\n" );
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document.write( "Easier, but in general you'll have to do them the long way.\r\n" );
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document.write( "Edwin

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