document.write( "Question 979445: we sell our emulsified product for $400 per ton. The product is 36% water and the water is free. What revenue are we actually making on the product and what is the calculation that can be used as we very the water content? \n" ); document.write( "
Algebra.Com's Answer #600730 by josmiceli(19441)\"\" \"About 
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The rate is \"+400+\" dollars/ton
\n" ); document.write( "\"+1+-+.36+=+.64+\" decimal part of a ton which is non-water
\n" ); document.write( "Rate for non-water part:
\n" ); document.write( "\"+400+%2F+.64+\" dollars/ton
\n" ); document.write( "\"+400%2F.64+=+625+\" dollars/ton
\n" ); document.write( "The actual rate for the non-water part is $625
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\n" ); document.write( "Let \"+R+\" = revenue from non-wtaer product
\n" ); document.write( "I'll say that \"+x+\" is the decimal part of a ton that I
\n" ); document.write( "will vary the water content by
\n" ); document.write( "Then I can say:
\n" ); document.write( "\"+R+=+400+%2F+%28+.64+%2B+x+%29+\"
\n" ); document.write( "Note that \"+-.64+%3C+x+%3C+.36+\"\r
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