document.write( "Question 979424: Anna forgot the code of a 3-digit lock on
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document.write( "her case (all digits ranging from 0 to 9).
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document.write( "She remembers that the first digit was
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document.write( "less than 5, the second digit was an odd
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document.write( "number, and the third one was either 7 or
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document.write( "8. There were no identical digits in the
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document.write( "code
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document.write( "How many different combinations could
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document.write( "possibly open her lock? \n" );
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Algebra.Com's Answer #600702 by anand429(138)![]() ![]() You can put this solution on YOUR website! Possibilities of 1st digit are 0,1,2,3,4 \n" ); document.write( "Possibilities of 2nd digit are 1,3,5,7,9 \n" ); document.write( "Possibilities of 3rd digit are 7,8 \n" ); document.write( "Now, considering no digits are identical, \n" ); document.write( "For 1st digit 0, 3rd digit-7. 2nd digit options, 1,3,5,9 Total cases=4 \n" ); document.write( "For 1st digit 0, 3rd digit-8. 2nd digit options, 1,3,5,7,9 Total cases=5 \n" ); document.write( "For 1st digit 1, 3rd digit-7. 2nd digit options, 3,5,9 Total cases=3 \n" ); document.write( "For 1st digit 1, 3rd digit-8. 2nd digit options, 3,5,7,9 Total cases=4 \n" ); document.write( "For 1st digit 2, 3rd digit-7. 2nd digit options, 1,3,5,9 Total cases=4 \n" ); document.write( "For 1st digit 2, 3rd digit-8. 2nd digit options, 1,3,5,7,9 Total cases=5 \n" ); document.write( "For 1st digit 3, 3rd digit-7. 2nd digit options, 1,5,9 Total cases=3 \n" ); document.write( "For 1st digit 3, 3rd digit-8. 2nd digit options, 1,5,7,9 Total cases=4 \n" ); document.write( "For 1st digit 4, 3rd digit-7. 2nd digit options, 1,3,5,9 Total cases=4 \n" ); document.write( "For 1st digit 4, 3rd digit-8. 2nd digit options, 1,3,5,7,9 Total cases=5\r \n" ); document.write( "\n" ); document.write( "Total no. of cases = 41 \n" ); document.write( " |