document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979146>Question 979146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man's age is three times the sum of the ages of his two sons, one of whom is twice as old as the other; in 12 years the sum of the son's ages will be three-fourths of their father's age. Find their respective ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600660 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600660\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man's age is three times the sum of the ages of his two sons, one of whom is twice as old as the other;<BR>\n" );
document.write( " in 12 years the sum of the son's ages will be three-fourths of their father's age.<BR>\n" );
document.write( " Find their respective ages.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let m = the man's age<BR>\n" );
document.write( "let s = a son's age<BR>\n" );
document.write( "\"one of whom is twice as old as the other;\" therefore<BR>\n" );
document.write( "2s = the other sons age<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "3s = the sum of the sons's ages<BR>\n" );
document.write( ":<BR>\n" );
document.write( "\"A man's age is three times the sum of the ages of his two sons,\"<BR>\n" );
document.write( "m = 3(3s)<BR>\n" );
document.write( "m = 9s<BR>\n" );
document.write( ":<BR>\n" );
document.write( "\"  in 12 years the sum of the son's ages will be three-fourths of their father's age.\"<BR>\n" );
document.write( "s + 12 + 2s + 12 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F4 ALIGN=MIDDLE  ALT=\"3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >(m + 12)<BR>\n" );
document.write( "3s + 24 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F4 ALIGN=MIDDLE  ALT=\"3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >(m + 12)<BR>\n" );
document.write( "multiply both sides by 4<BR>\n" );
document.write( "4(3s + 24) = 3(m + 12)<BR>\n" );
document.write( "12s + 96 = 3m + 36<BR>\n" );
document.write( "replace m with 9s<BR>\n" );
document.write( "12s + 96 = 27s + 36<BR>\n" );
document.write( "96 - 36 = 27s - 12s<BR>\n" );
document.write( "60 = 15s<BR>\n" );
document.write( "s = 60/15<BR>\n" );
document.write( "s = 4 yrs old is one son and then 8 yrs old is the other son<BR>\n" );
document.write( "Dad will be 3(12) = 36 yrs<BR>\n" );
document.write( " <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );