document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979326>Question 979326</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lesson is all about extracting the roots so correct me if im in the wrong lessons...<BR>\n" );
document.write( "But anyway hope anyone can solve my another question :) <BR>\n" );
document.write( "When the amount of (p) is invested at annual interest rate (r) compounded for (t) years, it will grow to an amount (a) given by the formula\r<BR>\n" );
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document.write( "A=P (1+r)^t\r<BR>\n" );
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document.write( "1 Suppose php 20,000 is invested  at an interested rate (r) compounded annually in 5 years, it will grow to php 60,000. What is the interest rate?\r<BR>\n" );
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document.write( "2 suppose in five years, the php 35,000 invested grows to php 75 345.75 , what is the interest rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600613 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600613\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Po{!+r/n}^nt\r<BR>\n" );
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document.write( "60000=20000{1+r}^5\r<BR>\n" );
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document.write( "3= (1+r)^5<BR>\n" );
document.write( "ln of both sides<BR>\n" );
document.write( "1.0986=5 ln (1+r)<BR>\n" );
document.write( "divide by 5 without rounding.\r<BR>\n" );
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document.write( "0.2197= ln (1+r)<BR>\n" );
document.write( "Raise both to e power<BR>\n" );
document.write( "1.2457= 1+ r<BR>\n" );
document.write( "0.2457=r or 24.6%<BR>\n" );
document.write( "1.246^5=3.003, so this checks.\r<BR>\n" );
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document.write( "second one will be less since doubling and  not trebling after 5 years. <BR>\n" );
document.write( "75345.75=35000 {1+r}^5<BR>\n" );
document.write( "divide by 35000 and take ln of both sides<BR>\n" );
document.write( "ln 2.153= 5 ln (1+r)<BR>\n" );
document.write( "0.7667=5 ln (1+r)<BR>\n" );
document.write( "divide by 5 and raise both to e power<BR>\n" );
document.write( "1.1657= 1+r<BR>\n" );
document.write( "r=0.1657 or 16.6% </SPAN>\n" );
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