document.write( "Question 979333: Find two consecutive positive integers such that the square of the second integer added to 5 times the first is equal to 121
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Algebra.Com's Answer #600608 by Boreal(15235)\"\" \"About 
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first integer is x
\n" ); document.write( "second is (x+1)
\n" ); document.write( "5x+(x+1)^2=121
\n" ); document.write( "5x+x^2+2x+1=121
\n" ); document.write( "5x+x^2+2x=120
\n" ); document.write( "x^2+7x-120=0
\n" ); document.write( "(x+15)(x-8)=0\r
\n" ); document.write( "\n" ); document.write( "x=-15, +8\r
\n" ); document.write( "\n" ); document.write( "Want only positive integers
\n" ); document.write( "8 and 9\r
\n" ); document.write( "\n" ); document.write( "square of second is 81
\n" ); document.write( "5 times the first is 40
\n" ); document.write( "They add to 121
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