document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979319>Question 979319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 11 ft. longer than twice the width.  If the perimeter is 94 ft, find the length and width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600589 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there<BR>\n" );
document.write( "Make the width = 'x'<BR>\n" );
document.write( "So, the length = 11 + 2x<BR>\n" );
document.write( "Perimeter = 2 x Length + 2 x Width<BR>\n" );
document.write( "94 = 2(11 + 2x) + 2x<BR>\n" );
document.write( "94 = 22 + 4x + 2x<BR>\n" );
document.write( "Collect like terms<BR>\n" );
document.write( "6x = 94 - 22<BR>\n" );
document.write( "6x = 72<BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( "Width = 12 ft<BR>\n" );
document.write( "Length = 35 ft<BR>\n" );
document.write( "Hope this helps:-) </SPAN>\n" );
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