document.write( "Question 979179: A barge movers 12 miles downstream and 8 miles upstream in a total
\n" ); document.write( "time of 2 hours. The current in the river is 2 mph. How fast does the barge
\n" ); document.write( "move in still water?
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Algebra.Com's Answer #600579 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "A barge movers 12 miles downstream and 8 miles upstream in a total
\n" ); document.write( "time of 2 hours. The current in the river is 2 mph. How fast does the barge
\n" ); document.write( "move in still water?
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Let barge's speed, in still water, be S
\n" ); document.write( "Time taken to journey downstream, with current: \"12%2F%28S+%2B+2%29\"
\n" ); document.write( "Time taken to journey upstream, against current: \"8%2F%28S+-+2%29\"
\n" ); document.write( "Since total time taken was 2 hours, we get: \"12%2F%28S+%2B+2%29+%2B+8%2F%28S+-+2%29+=+2\"
\n" ); document.write( "12(S - 2) + 8(S + 2) = 2(S + 2)(S - 2) ----- Multiplying by LCD, (S + 2)(S - 2)
\n" ); document.write( "\"12S+-+24+%2B+8S+%2B+16+=+2%28S%5E2+-+4%29\"
\n" ); document.write( "\"20S+-+8+=+2S%5E2+-+8\"
\n" ); document.write( "\"2S%5E2+-+20S+-+8+%2B+8+=+0\"
\n" ); document.write( "\"2S%5E2+-+20S+=+0\"
\n" ); document.write( "2S(S - 10) = 0
\n" ); document.write( "S - 10 = 0 OR 2S = 0 (ignore)
\n" ); document.write( "S, or speed of barge, in still water = \"highlight_green%2810%29\" mph \n" ); document.write( "
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