document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979287>Question 979287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Identify the vertices of the hyperbola<BR>\n" );
document.write( "(x + 4)^2/9 - (y -1)^2/16 = 1.\r<BR>\n" );
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document.write( "I think the center is (-4,1) but I don't remember how to find vertices </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600558 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The x^2 term is positive, so the hyperbola opens in the horizontal direction (along the x axis). That means we add and subtract 3 from the x coordinate of the center to get the vertices. Why 3? Because a^2 = 9 means a = 3.\r<BR>\n" );
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document.write( "(-4,1) ---> (-4+3,1) = (-1,1) is one vertex\r<BR>\n" );
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document.write( "(-4,1) ---> (-4-3,1) = (-7,1) is the other vertex </SPAN>\n" );
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