document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979188>Question 979188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The rectangle is 3x+1 units long and 2x-3 wide find its area </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600481 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "If a rectangle has a length of 3x + 1<BR>\n" );
document.write( "and a width of 2x - 3:<BR>\n" );
document.write( "Then its area = length x width<BR>\n" );
document.write( "(3x - 1)(2x - 3)<BR>\n" );
document.write( "=6x^2 - 9x - 2x + 3<BR>\n" );
document.write( "= 6x^2 - 11x + 3<BR>\n" );
document.write( "Hope this helps:-) </SPAN>\n" );
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