document.write( "Question 979024: A farmer has a certain number of eggs. If he counts in groups of 3, there will be 2 remaining eggs. If he count in groups of 4, 3 eggs will be remain. Remaining 5,6 if he count in groups of 6,7. How many eggs he has? \n" ); document.write( "
Algebra.Com's Answer #600423 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A farmer has a certain number of eggs. \n" ); document.write( " If he counts in groups of 3, there will be 2 remaining eggs. \n" ); document.write( " If he count in groups of 4, 3 eggs will be remain. \n" ); document.write( " Remaining 5,6 if he count in groups of 6,7. \n" ); document.write( " How many eggs he has? \n" ); document.write( ": \n" ); document.write( "Start with multiples of 7 plus 6 \n" ); document.write( "13, 20, 27, 34, 41, 48, 55, 62, 69, 76, 83, 90, 96 \n" ); document.write( "Then multiples of 6 plus 5 \n" ); document.write( "11, 17, 23, 29, 35, 41, 47, 53, 59, 65, 71, 77, 83, 89 \n" ); document.write( "Looks like 41 would be good candidate, counting in groups in 3 is ok, however, \n" ); document.write( "counting in groups of 4 does not give a remainder of 3 \n" ); document.write( "Let's try 83, that seems to work with counting by groups of 3 and 4 \n" ); document.write( ": \n" ); document.write( "He has 83 eggs \n" ); document.write( " |