document.write( "Question 979088: Candice Leaves on a road trip driving at 25 miles per hour . Four hours later , her sister leaves from the same location driving at 50 miles per hour . How long after Liz leaves home will she catch up to Candice ? \n" ); document.write( "
Algebra.Com's Answer #600385 by josmiceli(19441)\"\" \"About 
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Candice has a 4 hr head start on Liz
\n" ); document.write( "In that 4 hrs, Candice has traveled:
\n" ); document.write( "\"+d%5B1%5D+=+25%2A4+\"
\n" ); document.write( "\"+d%5B1%5D+=+100+\" mi
\n" ); document.write( "-------------------
\n" ); document.write( "Start a stop watch when Liz leaves
\n" ); document.write( "Let \"+d+\" = the distance in miles that
\n" ); document.write( "Liz travels until she catches Candice
\n" ); document.write( "Let \"+t+\" = time in hrs on the stop watch
\n" ); document.write( "when Liz catches Candice
\n" ); document.write( "-----------------------------------
\n" ); document.write( "Candice's equation:
\n" ); document.write( "(1) \"+d+-+100+=+25t+\"
\n" ); document.write( "Liz's equation:
\n" ); document.write( "(2) \"+d+=+50t+\"
\n" ); document.write( "----------------------
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+50t+-+100+=+25t+\"
\n" ); document.write( "(1) \"+25t+=+100+\"
\n" ); document.write( "(1) \"+t+=+4+\"
\n" ); document.write( "4 hrs after Liz leaves, she will catch Candice
\n" ); document.write( "-----------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+50t+\"
\n" ); document.write( "(2) \"+d+=+50%2A4+\"
\n" ); document.write( "(2) \"+d+=+200+\" mi
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+-+100+=+25t+\"
\n" ); document.write( "(1) \"+d+-+100+=+25%2A4+\"
\n" ); document.write( "(1) \"+d+=+100+%2B+100+\"
\n" ); document.write( "(1) \"+d+=+200+\" mi
\n" ); document.write( "OK
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