document.write( "Question 979088: Candice Leaves on a road trip driving at 25 miles per hour . Four hours later , her sister leaves from the same location driving at 50 miles per hour . How long after Liz leaves home will she catch up to Candice ? \n" ); document.write( "
Algebra.Com's Answer #600385 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Candice has a 4 hr head start on Liz \n" ); document.write( "In that 4 hrs, Candice has traveled: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------- \n" ); document.write( "Start a stop watch when Liz leaves \n" ); document.write( "Let \n" ); document.write( "Liz travels until she catches Candice \n" ); document.write( "Let \n" ); document.write( "when Liz catches Candice \n" ); document.write( "----------------------------------- \n" ); document.write( "Candice's equation: \n" ); document.write( "(1) \n" ); document.write( "Liz's equation: \n" ); document.write( "(2) \n" ); document.write( "---------------------- \n" ); document.write( "Substitute (2) into (1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "4 hrs after Liz leaves, she will catch Candice \n" ); document.write( "----------------- \n" ); document.write( "check: \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "and \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |