document.write( "Question 979070: An aeroplane flies 3500 km in the same time a train covers 600 km.If the speed of the aeroplane is 50 km/h more than five times the speed of the train ,what are the speeds of the train and the aeroplane? \n" ); document.write( "
Algebra.Com's Answer #600361 by Theo(13342)![]() ![]() You can put this solution on YOUR website! rate * t = distance \n" ); document.write( "rt = d \n" ); document.write( "for the plane: \n" ); document.write( "rt = d becomes rt = 3500 \n" ); document.write( "for the train: \n" ); document.write( "rt = d becomes rt = 600 \n" ); document.write( "since the time each takes is the same, we'll solve for t. \n" ); document.write( "for the plane, t = d/r = 3500/r \n" ); document.write( "for the train, t = d/r = 600/r \n" ); document.write( "since t is the same for each, then t = t, or their equivalents: \n" ); document.write( "3500/r = 600/r \n" ); document.write( "the rates are different, so we'll need to distinguish beween the two rates. \n" ); document.write( "we'll call r for the plane r1. \n" ); document.write( "we'll call r for the train r2. \n" ); document.write( "the equation becomes: \n" ); document.write( "3500/r1 = 600/r2 \n" ); document.write( "we are told that the plan travels 5 times as fast as the train plus 50 km/hr. \n" ); document.write( "the equation for that is: \n" ); document.write( "r1 = 5r2 + 50 \n" ); document.write( "we'll replace r1 with 5r2 + 50 in the equation of 3500/r1 = 600/r2 to get: \n" ); document.write( "3500 / (5r2+50) = 600 / r2 \n" ); document.write( "we'll cross multiply to get: \n" ); document.write( "3500 * r2 = 600 * (5r2 + 50) \n" ); document.write( "simplify to get: \n" ); document.write( "3500r2 = 3000r2 + 30000 \n" ); document.write( "subtract 3000r2 from both sides of this equation to get: \n" ); document.write( "500r2 = 30000 \n" ); document.write( "solve for r2 to get: \n" ); document.write( "r2 = 60 \n" ); document.write( "since r1 = 5r2 + 50, this means that r1 = 350. \n" ); document.write( "the train travels at 60 kmph. \n" ); document.write( "the plan travels at 350kmph. \n" ); document.write( "now that we know the rates and distance, we can solve for time. \n" ); document.write( "for the plane: \n" ); document.write( "350*t = 3500 \n" ); document.write( "solve for t to get t = 10 hours. \n" ); document.write( "for the train: \n" ); document.write( "60*t = 600 \n" ); document.write( "solve for t to get 10 hours. \n" ); document.write( "the time for both is 10 hours as it should be since they both took the same amount of time. \n" ); document.write( "this confirms our calculations are correct. \n" ); document.write( "our solution is: \n" ); document.write( "the plane travels at 350kmph \n" ); document.write( "the train travels at 60kmph \n" ); document.write( " |