document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979008>Question 979008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Lucas is 9 years older than three times his son’s age.  In 14 years, the age of Lucas will be 6 years more than twice his son’s age.  Find their present ages.<BR>\n" );
document.write( "PARTIAL SOLUTION<BR>\n" );
document.write( "x= son's age. So lucas age= 3x+9<BR>\n" );
document.write( "After 14 years, son age= x +14, lucas age= 2(x+14)+6<BR>\n" );
document.write( "Not sure how to move ahead </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600333 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600333\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The work here to solve was wrong, TWICE.\r<BR>\n" );
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document.write( "For a much better and correct solution, see the solution to the identical question here:\r<BR>\n" );
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document.write( "http://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.979009.html\r<BR>\n" );
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