document.write( "Question 978968: Here is the question I'm stuck on:\r
\n" ); document.write( "\n" ); document.write( "Give an equation of each line described:\r
\n" ); document.write( "\n" ); document.write( "a) Through the point (2,5) with slope -3/4\r
\n" ); document.write( "\n" ); document.write( "b) through the points (3,-1) and (0,6)\r
\n" ); document.write( "\n" ); document.write( "c) horizontal line through (-2,-7)\r
\n" ); document.write( "\n" ); document.write( "d) line through the point (6,5) and parallel to the line 2x + 3y = 7\r
\n" ); document.write( "\n" ); document.write( "e) line through the point (4,1) and perpendicular to the line x + 5y = 1\r
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\n" ); document.write( "\n" ); document.write( "That is all. Thank you so much for taking time out of your day to help me!
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Algebra.Com's Answer #600313 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
a) Through the point (\"2\",\"5\") with slope \"m=-3%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=mx%2Bb\"
\n" ); document.write( "if slope \"m=-3%2F4\", we have
\n" ); document.write( "\"y=-%283%2F4%29x%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "now use given point (\"x\",\"y\")=(\"2\",\"5\") and find \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"5=-%283%2F4%292%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"5=-%283%2F2%29%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"5%2B%283%2F2%29=b\"\r
\n" ); document.write( "\n" ); document.write( "\"b=10%2F2%2B3%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"b=13%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"b=6.5\"\r
\n" ); document.write( "\n" ); document.write( "so, your equation is \"y=-%283%2F4%29x%2B6.5\"\r
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\n" ); document.write( "\n" ); document.write( "b) through the points (\"3\",\"-1\") and (\"0\",\"6\")\r
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Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (3, -1) and (x2, y2) = (0, 6).
\n" ); document.write( " Slope a is .
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"-2.33333333333333%2A3+%2Bb+=+6\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=-1--2.33333333333333%2A3+=+6\".
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\n" ); document.write( " y=(-2.33333333333333)x + (6)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "c) horizontal line through (\"-2\",\"-7\")\r
\n" ); document.write( "\n" ); document.write( "For a horizontal line equation will be \"y=a\" where \"a\" is a constant.
\n" ); document.write( "For the line to pass through the point (\"-2\",\"-7\") \"y\" should be equal to \"-7\".\r
\n" ); document.write( "\n" ); document.write( "Your line should be
\n" ); document.write( "\"y=-7\"\r
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\n" ); document.write( "\n" ); document.write( "d) line through the point (\"6\",\"5\") and parallel to the line \"2x+%2B+3y+=+7\"\r
\n" ); document.write( "\n" ); document.write( "\"3y+=-2x%2B+7\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=-%282%2F3%29x%2B+7%2F3\"\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"-2%2F3\" (its from the slope of \"y=%28-2%2F3%29%2Ax%2B7%2F3\" which is also \"-2%2F3\").\n" ); document.write( "Also since the unknown line goes through (6,5), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-5=%28-2%2F3%29%2A%28x-6%29\" Plug in \"m=-2%2F3\", \"x%5B1%5D=6\", and \"y%5B1%5D=5\"
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\n" ); document.write( " \"y-5=%28-2%2F3%29%2Ax%2B%282%2F3%29%286%29\" Distribute \"-2%2F3\"
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\n" ); document.write( " \"y-5=%28-2%2F3%29%2Ax%2B12%2F3\" Multiply
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\n" ); document.write( " \"y=%28-2%2F3%29%2Ax%2B12%2F3%2B5\"Add \"5\" to both sides to isolate y
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\n" ); document.write( " \"y=%28-2%2F3%29%2Ax%2B12%2F3%2B15%2F3\" Make into equivalent fractions with equal denominators
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\n" ); document.write( " \"y=%28-2%2F3%29%2Ax%2B27%2F3\" Combine the fractions
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\n" ); document.write( " \"y=%28-2%2F3%29%2Ax%2B9\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is parallel to \"y=%28-2%2F3%29%2Ax%2B7%2F3\" and goes through (\"6\",\"5\") is \"y=%28-2%2F3%29%2Ax%2B9\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%28-2%2F3%29%2Ax%2B7%2F3\" and \"y=%28-2%2F3%29%2Ax%2B9\"
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\n" ); document.write( "
\n" ); document.write( " graph of the given equation \"y=%28-2%2F3%29%2Ax%2B7%2F3\" (red) and graph of the line \"y=%28-2%2F3%29%2Ax%2B9\"(green) that is parallel to the given graph and goes through (\"6\",\"5\")
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\n" ); document.write( "\n" ); document.write( "e) line through the point (\"4\",\"1\") and perpendicular to the line \"x+%2B+5y+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"5y+=-x%2B+1\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=-%281%2F5%29x%2B+1%2F5\"\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"-1%2F5\", you can find the perpendicular slope by this formula:
\n" ); document.write( "
\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=-1%2F%28-1%2F5%29\" So plug in the given slope to find the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%285%2F-1%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
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\n" ); document.write( " \"m%5Bp%5D=5%2F1\" Multiply the fractions.
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\n" ); document.write( " So the perpendicular slope is \"5\"
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\n" ); document.write( " So now we know the slope of the unknown line is \"5\" (its the negative reciprocal of \"-1%2F5\" from the line \"y=%28-1%2F5%29%2Ax%2B1%2F5\").\n" ); document.write( "Also since the unknown line goes through (4,1), we can find the equation by plugging in this info into the point-slope formula
\n" ); document.write( "
\n" ); document.write( " Point-Slope Formula:
\n" ); document.write( "
\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
\n" ); document.write( "
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\n" ); document.write( "
\n" ); document.write( " \"y-1=5%2A%28x-4%29\" Plug in \"m=5\", \"x%5B1%5D=4\", and \"y%5B1%5D=1\"
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\n" ); document.write( "
\n" ); document.write( " \"y-1=5%2Ax-%285%29%284%29\" Distribute \"5\"
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\n" ); document.write( " \"y-1=5%2Ax-20\" Multiply
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\n" ); document.write( " \"y=5%2Ax-20%2B1\"Add \"1\" to both sides to isolate y
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\n" ); document.write( " \"y=5%2Ax-19\" Combine like terms
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=%28-1%2F5%29%2Ax%2B1%2F5\" and goes through (\"4\",\"1\") is \"y=5%2Ax-19\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%28-1%2F5%29%2Ax%2B1%2F5\" and \"y=5%2Ax-19\"
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\n" ); document.write( "
\n" ); document.write( " graph of the given equation \"y=%28-1%2F5%29%2Ax%2B1%2F5\" (red) and graph of the line \"y=5%2Ax-19\"(green) that is perpendicular to the given graph and goes through (\"4\",\"1\")
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