document.write( "Question 978945: 6 year ago Simon is twice as old as cara 4years from now his age will be 10 less twice Clara's age what are Simons and Clara's age \n" ); document.write( "

Algebra.Com's Answer #600308 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+s+\"$ = Simon's age now
\n" ); document.write( "Let $\"+c+\"$ = Clara's age now
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\n" ); document.write( "(1) $\"+s+-+6+=+2%2A%28+c+-+6+%29+\"$
\n" ); document.write( "(2) $\"+s+%2B+4+=+2%2A%28+c+%2B+4+%29+-+10+\"$
\n" ); document.write( "-----------------------------
\n" ); document.write( "(1) $\"+s+-+6+=+2c+-+12+\"$
\n" ); document.write( "(1) $\"+2c+-+s+=+6+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+s+%2B+4+=+2c+%2B+8+-+10+\"$
\n" ); document.write( "(2) $\"+s+%2B+4+=+2c+-+2+\"$
\n" ); document.write( "(2) $\"+2c+-+s+=+6+\"$
\n" ); document.write( "-----------------
\n" ); document.write( "I get 2 indentical equations, which is
\n" ); document.write( "just 1 equation, really, but I have 2
\n" ); document.write( "unknowns, so any $\"+c+\"$ and $\"+s+\"$
\n" ); document.write( "that satisfies the equation works.
\n" ); document.write( " $\"+2%2A12+-+18+=+6+\"$
\n" ); document.write( "So, I could say:
\n" ); document.write( "Clara is 12
\n" ); document.write( "Simon is 18
\n" ); document.write( "Many other ages would work, so I'm
\n" ); document.write( "saying there are no unique answers
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\n" ); document.write( "Very strange problem. I would get another
\n" ); document.write( "opinion on this. Good luck\r
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