document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=11679>Question 11679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the mean and the standard deviation of a continuous random variable that is normally distributed are 26 and 6, find the interval that contains 95% of the distributions.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6003 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6003\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   Assume the 95% interval is (mu -x,mu+x) where mu is the mean <BR>\n" );
document.write( "  We have x/6 = 1.96 [ this value corresponding to 0.95 from the Table]<BR>\n" );
document.write( "  so, x = 1.96*6 = 11.76<BR>\n" );
document.write( "  Hence,the solution interval is (26- 11.76,26+11.76)<BR>\n" );
document.write( "  = (14.24, 37.76)\r<BR>\n" );
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