document.write( "Question 83512: A passenger train travels 150 miles in the same time that a frieght train travels 100 miles. If the frieght train travels 20 mph slower than the passenger train, what is the speed of the passenger train? \n" ); document.write( "
Algebra.Com's Answer #60029 by stanbon(75887)\"\" \"About 
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A passenger train travels 150 miles in the same time that a frieght train travels 100 miles. If the frieght train travels 20 mph slower than the passenger train, what is the speed of the passenger train?
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\n" ); document.write( "Passenger train DATA:
\n" ); document.write( "distance = 150 mi ; Rate = x mph ; time = d/r = 150/x hrs
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\n" ); document.write( "Freight train DATA:
\n" ); document.write( "disance = 100 mi ; Rate = x-20 mph ; time = d/r = 100/(x-20) hrs
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\n" ); document.write( "EQUATION:
\n" ); document.write( "time = time
\n" ); document.write( "150/x = 100/(x-20)
\n" ); document.write( "3/x = 2/(x-20)
\n" ); document.write( "3x-60 = 2x
\n" ); document.write( "x=60 mph (passenger train rate)
\n" ); document.write( "x-20 = 40 mph (freight train rate)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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