document.write( "Question 978879: x+y+z=192
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document.write( "x=y+z
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document.write( "x=3z
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document.write( "solve by using elimination… \n" );
document.write( "
Algebra.Com's Answer #600234 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Here's one exactly like it that you can use as a guide\r\n" ); document.write( "to solve yours. I'm just changing your 192 to 40.\r\n" ); document.write( "\r\n" ); document.write( "x+y+z=40\r\n" ); document.write( "x=y+z\r\n" ); document.write( "x=4z\r\n" ); document.write( "\r\n" ); document.write( "Notice that the first two equations both have (y+z)\r\n" ); document.write( "I'll put them in parentheses to make it clear:\r\n" ); document.write( "\r\n" ); document.write( "x+(y+z)=40\r\n" ); document.write( "x=(y+z)\r\n" ); document.write( "x=4z\r\n" ); document.write( "\r\n" ); document.write( "Since the second equation tells us that (y+z)=x, we can\r\n" ); document.write( "substitute x for (y+z) in the first equation:\r\n" ); document.write( "\r\n" ); document.write( "x+(x)=40\r\n" ); document.write( "2x=40\r\n" ); document.write( " x=20\r\n" ); document.write( "\r\n" ); document.write( "Then substitute 20 for x in x=4z\r\n" ); document.write( "\r\n" ); document.write( "20=4z\r\n" ); document.write( " 5=z\r\n" ); document.write( "\r\n" ); document.write( "Finally substitute x=20 and z=5 in x=(y+z)\r\n" ); document.write( "\r\n" ); document.write( "20=(y+5)\r\n" ); document.write( "20=y+5\r\n" ); document.write( "15=y\r\n" ); document.write( "\r\n" ); document.write( "Now do yours exactly the same way. {Yours will have bigger numbers\r\n" ); document.write( "because 192 is bigger than 40\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |