document.write( "Question 978778: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, the wind is still blowing at the same speed, so the return trip takes only 1 hour 12 minutes. What is his speed in still air, and how fast is the wind blowing?\r
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\n" ); document.write( "\n" ); document.write( "Your answer is
\n" ); document.write( "his speed equals
\n" ); document.write( "the wind speed equals
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Algebra.Com's Answer #600159 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
r*t=d
\n" ); document.write( "with the wind
\n" ); document.write( "(r+w)*1.2=180
\n" ); document.write( "(r+w)=180/1.2
\n" ); document.write( "r+w=150.0
\n" ); document.write( "against the wind
\n" ); document.write( "(r-w)*2=180
\n" ); document.write( "(r-w)=180/2\r
\n" ); document.write( "\n" ); document.write( "r-w=90
\n" ); document.write( "r+w=150.0
\n" ); document.write( "add
\n" ); document.write( "r+r=150.0+90
\n" ); document.write( "2r=240.0
\n" ); document.write( "r=120.0 mph rate\r
\n" ); document.write( "\n" ); document.write( "120-w=90
\n" ); document.write( "w=120-90
\n" ); document.write( "w=30 mph wind
\n" ); document.write( "check
\n" ); document.write( "(120+30)*1.2=180
\n" ); document.write( "150*1.2=180
\n" ); document.write( "180.0=180
\n" ); document.write( "ok
\n" ); document.write( "(r-w)*2=180
\n" ); document.write( "(120-30)*2=180
\n" ); document.write( "90*2=180
\n" ); document.write( "180=180
\n" ); document.write( "ok
\n" ); document.write( "codedrtdtt
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