document.write( "Question 83178: express each of the following as the same function of a positive acute angle:
\n" ); document.write( " a. cos 112degrees 33'
\n" ); document.write( "b.tan 310degrees
\n" ); document.write( "c.cot 138degrees 15' 10\"
\n" ); document.write( "d.sin (-140degrees)
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Algebra.Com's Answer #60012 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "express each of the following as the same function\r\n" );
document.write( "of a positive acute angle:\r\n" );
document.write( "a. cos( 112°33')\r\n" );
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document.write( "That angle is in the second quadrant.\r\n" );
document.write( "The cosine is negative in the second quadrant.\r\n" );
document.write( "The reference angle is found by subtracting it from 180°\r\n" );
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document.write( " 180°       179°60'\r\n" );
document.write( "-112°30' = -112°33'\r\n" );
document.write( "-------------------\r\n" );
document.write( "             67°27'\r\n" );
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document.write( "Therefore cos(112°33) = -cos(67°27') \r\n" );
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document.write( "--------------------------------------------\r\n" );
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document.write( "b.tan(310°)\r\n" );
document.write( "That angle is in the fourth quadrant.\r\n" );
document.write( "The tangent is negative in the fourth quadrant.\r\n" );
document.write( "The reference angle is found by subtracting 310° from 360°\r\n" );
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document.write( " 360°              \r\n" );
document.write( "-310                  \r\n" );
document.write( "-----                  \r\n" );
document.write( "  50°\r\n" );
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document.write( "Therefore tan(310°) = -tan(50°)\r\n" );
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document.write( "-------------------------------------------\r\n" );
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document.write( "c.cot(138°15'10\")\r\n" );
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document.write( "That angle is in the second quadrant.\r\n" );
document.write( "The cotangent is negative in the second quadrant.\r\n" );
document.write( "The reference angle is found by subtracting it from 180°\r\n" );
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document.write( " 180°          179°59'60\"\r\n" );
document.write( "-138°15'10\" = -138°15'10\"\r\n" );
document.write( "-------------------------\r\n" );
document.write( "                41°44'50\"\r\n" );
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document.write( "Therefore cot(138°15'10\") = -cot(41°44'50) \r\n" );
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document.write( "------------------------------------------------\r\n" );
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document.write( "d.sin (-140°)\r\n" );
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document.write( "That angle is in the third quadrant.\r\n" );
document.write( "The sine is negative in the third quadrant.\r\n" );
document.write( "The reference angle is found by subtracting 140° from 180°\r\n" );
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document.write( " 180°              \r\n" );
document.write( "-140°                  \r\n" );
document.write( "-----                  \r\n" );
document.write( "  40°\r\n" );
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document.write( "Therefore sin(-140°) = -sin(40°)\r\n" );
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document.write( "Edwin
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