document.write( "Question 978751: The opposite pairs of sides of a square are increased by 40% and 30% respectively.The area of the resulting rectangle exceeds the area of square by?
\n" ); document.write( "a.42%
\n" ); document.write( "b.62%
\n" ); document.write( "c.82%
\n" ); document.write( "d.72%
\n" ); document.write( "

Algebra.Com's Answer #600113 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Say you have a square that measures
\n" ); document.write( "40m x 40m
\n" ); document.write( "Area = 1600m^2
\n" ); document.write( "If you increase one pair of sides by 40%
\n" ); document.write( "they will equal 56m
\n" ); document.write( "The other pair of sides increased by
\n" ); document.write( "30% will equal 52m
\n" ); document.write( "New area = 56 x 52 = 2912m^2
\n" ); document.write( "2912m^2 - 1600m^2
\n" ); document.write( "= 1312m^2
\n" ); document.write( "=1312m^2/1600m^2 x 100
\n" ); document.write( "= 82%
\n" ); document.write( "Hope this helps:-)
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