document.write( "Question 978681: jessica and cynthia work in a pet shop. it takes jessica 6 hours to groom all the pets but cynthia needs 8 hours to groom them. if jessica starts to groom 1 hour before cynthia joins, how long will it take them to finish? \n" ); document.write( "
Algebra.Com's Answer #600056 by ankor@dixie-net.com(22740)\"\" \"About 
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jessica and cynthia work in a pet shop.
\n" ); document.write( " it takes jessica 6 hours to groom all the pets but cynthia needs 8 hours to groom them.
\n" ); document.write( " if jessica starts to groom 1 hour before cynthia joins, how long will it take them to finish?
\n" ); document.write( ":
\n" ); document.write( "let t = time it takes them to finish (C's working time)
\n" ); document.write( "then
\n" ); document.write( "t+1 = J's working time
\n" ); document.write( "let 1 = completed job (all pets groomed)
\n" ); document.write( ":
\n" ); document.write( "A shared work equation, each does a fraction of the job, the two fractions add up to 1
\n" ); document.write( "\"%28%28t%2B1%29%29%2F6\" + \"t%2F8\" = 1
\n" ); document.write( "Multiply by the least common multiple of 6 and 8, 24. cancel the denominators
\n" ); document.write( "4(t+1) + 3t = 24
\n" ); document.write( "4t + 4 + 3t = 24
\n" ); document.write( "4t + 3t = 24 - 4
\n" ); document.write( "7t = 20
\n" ); document.write( "t = 20/7
\n" ); document.write( "t = 2\"6%2F7\" hrs, which is: 2 + \"6%2F7\"*60 = 2 hrs 51.43 min to finish the job
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