document.write( "Question 978681: jessica and cynthia work in a pet shop. it takes jessica 6 hours to groom all the pets but cynthia needs 8 hours to groom them. if jessica starts to groom 1 hour before cynthia joins, how long will it take them to finish? \n" ); document.write( "
Algebra.Com's Answer #600056 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! jessica and cynthia work in a pet shop. \n" ); document.write( " it takes jessica 6 hours to groom all the pets but cynthia needs 8 hours to groom them. \n" ); document.write( " if jessica starts to groom 1 hour before cynthia joins, how long will it take them to finish? \n" ); document.write( ": \n" ); document.write( "let t = time it takes them to finish (C's working time) \n" ); document.write( "then \n" ); document.write( "t+1 = J's working time \n" ); document.write( "let 1 = completed job (all pets groomed) \n" ); document.write( ": \n" ); document.write( "A shared work equation, each does a fraction of the job, the two fractions add up to 1 \n" ); document.write( " \n" ); document.write( "Multiply by the least common multiple of 6 and 8, 24. cancel the denominators \n" ); document.write( "4(t+1) + 3t = 24 \n" ); document.write( "4t + 4 + 3t = 24 \n" ); document.write( "4t + 3t = 24 - 4 \n" ); document.write( "7t = 20 \n" ); document.write( "t = 20/7 \n" ); document.write( "t = 2 \n" ); document.write( " \n" ); document.write( " |