document.write( "Question 978672: Tiana invests $1900 in one account and $1400 in an account paying 3 % higher interest. At the end of one year she had earned $372 in interest. At what rates did she invest?
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Algebra.Com's Answer #600049 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Tiana invests $ $\"1900\"$ in one account at rate $\"x\"$ % and $ $\"1400\"$ in an account paying $\"3\"$ % higher interest. \r
\n" ); document.write( "\n" ); document.write( "At the end of one year she had earned $ $\"372\"$ in interest.
\n" ); document.write( " $\"%28x%2F100%291900%2B%28x%2F100%2B3%2F100%291400=372\"$
\n" ); document.write( " $\"%28x%2F1%2919%2B%28%28x%2B3%29%2F1%2914=372\"$
\n" ); document.write( " $\"19x%2B%28x%2B3%29%2A14=372\"$
\n" ); document.write( " $\"19x%2B14x%2B42=372\"$
\n" ); document.write( " $\"33x=372-42\"$
\n" ); document.write( " $\"33x=330\"$
\n" ); document.write( " $\"x=330%2F33\"$
\n" ); document.write( " $\"x=10\"$ % \r
\n" ); document.write( "\n" ); document.write( "and an account paying $\"3\"$ % higher interest is $\"x%2B3=13\"$ % \r
\n" ); document.write( "\n" ); document.write( " she invest at $\"10\"$ % and $\"13\"$ % \r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( " $\"10\"$ % of $ $\"1900\"$ is $ $\"%2810%2F100%291900=10%2A19=190\"$
\n" ); document.write( " $\"13\"$ % of $ $\"1400\"$ is $ $\"%2813%2F100%291400=13%2A14=182\"$ \r
\n" ); document.write( "\n" ); document.write( "and $\"190%2B182=372\"$ which confirms our solution\r
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