document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=978663>Question 978663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sample from a refuge deposit near the Strait of Magellan has 60% of the carbon 14 of a contemporary living sample. How old was the sample?\r<BR>\n" );
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document.write( "Please help! Thank you!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600040 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Poe^rt<BR>\n" );
document.write( "P/Po=1/2, which is half as much left<BR>\n" );
document.write( "t=5730 years\r<BR>\n" );
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document.write( "0.5=e^5730r<BR>\n" );
document.write( "ln of both sides<BR>\n" );
document.write( "-0.693=5730r<BR>\n" );
document.write( "r=-0.0001209\r<BR>\n" );
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document.write( "Want P/Po=0.6<BR>\n" );
document.write( "0.6=e^(0.0001209)t<BR>\n" );
document.write( "ln of both sides<BR>\n" );
document.write( "-0.5108= -0.0001209<BR>\n" );
document.write( "4224.97 years or 4225 years<BR>\n" );
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