document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83473>Question 83473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The foci of a hyperbola<BR>\n" );
document.write( "x^2/16 -(y-2)^2/9=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60004 by </B><A HREF=/tutors/aboutme.mpl?userid=akhilreddy90><B>akhilreddy90(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=akhilreddy90><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60004\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> using the formulae for eccentricity we get e=4/5<BR>\n" );
document.write( "then for standard hyperbola foci r =(ae,o) or (-ae,o)<BR>\n" );
document.write( "but for this one, X=ae<BR>\n" );
document.write( "i.e,x=4*4/5=4<BR>\n" );
document.write( "thenY=o,but  y=2\r<BR>\n" );
document.write( "\n" );
document.write( "therfore,foci r (5,2),(-5,2) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );