document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=978603>Question 978603</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When the amount of (p) is invested at annual interest rate (r) compounded for (t) years, it will grow to. An amount (a) given by the formula<BR>\n" );
document.write( "A=P (1+r)^t<BR>\n" );
document.write( "1 suppose php 20,000 is invested  at annual interest rate(r) compounded annually<BR>\n" );
document.write( "In 3 years, it grows to php 23,152. What is the interest rate?<BR>\n" );
document.write( "2. Suppose in 10 years. The php 20,000 invested grows to php 35816.95, what is the interest rate?\r<BR>\n" );
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document.write( "Hello :)<BR>\n" );
document.write( "Hope you can help me solve this problem :)<BR>\n" );
document.write( "Im really thankful if anyone can answer it :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #600016 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=600016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 23152=20000(1+r)^3<BR>\n" );
document.write( "divide by 20000<BR>\n" );
document.write( "1.1576=(1+r)^3\r<BR>\n" );
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document.write( "ln of both sides, remembering that ln of an exponent puts the exponent in front.<BR>\n" );
document.write( "0.1463=3 ln (1+r)<BR>\n" );
document.write( "divide by 3<BR>\n" );
document.write( "0.04878=ln(1+r)\r<BR>\n" );
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document.write( "raise both to e power\r<BR>\n" );
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document.write( "1.0499=1+r<BR>\n" );
document.write( "r=0.0499 or probably 5%.\r<BR>\n" );
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document.write( "Check:  20000(1.05^3)=23152\r<BR>\n" );
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document.write( "35816.95=20000(1+r)^10<BR>\n" );
document.write( "Do the same way<BR>\n" );
document.write( "1.79084=(1+r)^10.   Without rounding, take the ln of the left and then divide by 10, since the right will become 10 ln (1+r)\r<BR>\n" );
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document.write( "0.0583=ln(1+r)<BR>\n" );
document.write( "now raise both to e power<BR>\n" );
document.write( "1.05999=1+r<BR>\n" );
document.write( "r=6%\r<BR>\n" );
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document.write( "20000(1.06)^10=35816.95<BR>\n" );
document.write( " </SPAN>\n" );
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