document.write( "Question 978616: A jar has 54 pieces of candy consisting of 2 types: peppermint and caramel. The probability of randomly picking a peppermint candy is twice as high as picking a caramel. How many pieces of caramel candy needs to be added to the jar so that the probability of picking a peppermint candy becomes 3/5?\r
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Algebra.Com's Answer #599992 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x=caramel \n" ); document.write( "2x=peppermint \n" ); document.write( "Those are probabilities. \n" ); document.write( "There are 36 peppermint and 18 caramel (54 total). 3x=54, x=18; 2x=36.\r \n" ); document.write( "\n" ); document.write( "I will now add a pieces of caramel until the fraction of peppermint is now\r \n" ); document.write( "\n" ); document.write( "18+a/54+a will be 2/5, since if the probability of peppermint is 3/5, caramel will be 2/5. \n" ); document.write( "Cross multiply: 2(54+a)=5(18+a) \n" ); document.write( "108+2a=90+5a \n" ); document.write( "18=3a \n" ); document.write( "6=a\r \n" ); document.write( "\n" ); document.write( "add 6 pieces of caramel, and total is 60. \n" ); document.write( "36 are peppermint. \n" ); document.write( "That is 3/5. \n" ); document.write( " |