document.write( "Question 978601: It takes 10 hours for a bakery owner to finish the orders for Christmas. After he worked for 4 hours, his wife came to help him. He completed the orders with her help in another 4 hours. How long would it have taken if his wife had done the orders by herself? \n" ); document.write( "
Algebra.Com's Answer #599990 by richwmiller(17219)\"\" \"About 
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He worked 4 hours leaving 6 more hours for him.
\n" ); document.write( "rate for A alone 6 baker
\n" ); document.write( "rate for A & B together 4
\n" ); document.write( "1/a+1/b=1/x
\n" ); document.write( "1/6+1/b=1/4
\n" ); document.write( "1/b=1/4-1/6
\n" ); document.write( "1/b=6/24-4/24
\n" ); document.write( "1/b=2/24
\n" ); document.write( "1/b=1/12
\n" ); document.write( "b=12
\n" ); document.write( "rate for wife alone 12 hours for the remaining 6 hours
\n" ); document.write( "check
\n" ); document.write( "1/6+1/12=1/4
\n" ); document.write( "12/72+6/72=1/4
\n" ); document.write( "18/72=1/4
\n" ); document.write( "ok
\n" ); document.write( "codewa
\n" ); document.write( "But we want to know how long it would have taken her for the whole job not just part of it
\n" ); document.write( "he works twice as fast as she does so the job that takes him 10 hours alone would take her 20 hours alone.\r
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