document.write( "Question 978574: There are 60% acid solution and 80% acid solution. Find the volume of each solution if both of them are mixed and the result is 20 liters of 65% acid solution. \n" ); document.write( "
Algebra.Com's Answer #599946 by richwmiller(17219)\"\" \"About 
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By substitution
\n" ); document.write( "We know the total amount is 20 liters
\n" ); document.write( "We know the percentage of the total amount is 65%
\n" ); document.write( "We know the total amount has 13 liters of 100%
\n" ); document.write( "We want to know the amount of solution at 60%
\n" ); document.write( "We want to know the amount of solution at 80%
\n" ); document.write( "x+y=20,
\n" ); document.write( "0.6*x+0.8*y=0.65*20
\n" ); document.write( "0.6*x+0.8*y=13
\n" ); document.write( "x=20-y
\n" ); document.write( "0.6*(20-y)+0.8*y=13
\n" ); document.write( "12-0.6y+0.8*y=13
\n" ); document.write( "0.2*y=1
\n" ); document.write( "We now know amount of solution at 80%
\n" ); document.write( "y=5 liters at 80%
\n" ); document.write( "x=20-y
\n" ); document.write( "We now know amount of solution at 60%
\n" ); document.write( "x=15 liters at 60%
\n" ); document.write( "check
\n" ); document.write( "0.6*15+0.8*5=0.65*20
\n" ); document.write( "9+4=13
\n" ); document.write( "13=13
\n" ); document.write( "ok\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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