document.write( "Question 978559: Mary invested 10000 part at 4% and part at 5% for 1 year. How much was invested in each acct if interest earned in the 5% acct was 284 greater than 4% acct. the \n" ); document.write( "

Algebra.Com's Answer #599930 by richwmiller(17219) $\"\"$ $\"About$

You can put this solution on YOUR website!
We know the total amount of money invested. $10000
\n" ); document.write( "x+y=10000,
\n" ); document.write( "We know that the difference in interest earned by the two accounts is $284
\n" ); document.write( "0.05*x-0.04*y=284
\n" ); document.write( "x=10000-y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.05*(10000-y)-0.04*y=284
\n" ); document.write( "We multiply out
\n" ); document.write( "500-0.05y-0.04*y=284
\n" ); document.write( "We combine like terms.
\n" ); document.write( "216=0.09*y
\n" ); document.write( "Isolate y
\n" ); document.write( "y=216/0.09
\n" ); document.write( "y=2400 at 4%
\n" ); document.write( "Calculate x
\n" ); document.write( "x=10000-2400
\n" ); document.write( "x=7600 at 5%
\n" ); document.write( "Interest earned at 5% is 380
\n" ); document.write( "Interest earned at 4% is 96
\n" ); document.write( "We check
\n" ); document.write( "0.05*7600-0.04*2400=284
\n" ); document.write( "380-96=284
\n" ); document.write( "284=284
\n" ); document.write( "Since this statement is TRUE and neither x nor y is negative then all is well
\n" ); document.write( "codeintdy
\n" ); document.write( " \n" ); document.write( "

\n" );