document.write( "Question 978562: Mary invested 10000 part at 4% and part at 5% for 1 year. How much was invested in each acct if interest earned in the 5% account was 284 greater than in 4% account? \n" ); document.write( "
Algebra.Com's Answer #599919 by Boreal(15235)\"\" \"About 
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x invested at 4%
\n" ); document.write( "10000-x invested at 5%\r
\n" ); document.write( "\n" ); document.write( ".04 x+284=(0.05)(10000-x)
\n" ); document.write( "0.04x +284=500-0.05x
\n" ); document.write( "0.09x=216
\n" ); document.write( "x=2400
\n" ); document.write( "10000-x=7600\r
\n" ); document.write( "\n" ); document.write( "Check 4% of 2400=$96
\n" ); document.write( "5% of 7600=$380\r
\n" ); document.write( "\n" ); document.write( "The difference is $284.
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