document.write( "Question 978562: Mary invested 10000 part at 4% and part at 5% for 1 year. How much was invested in each acct if interest earned in the 5% account was 284 greater than in 4% account? \n" ); document.write( "
Algebra.Com's Answer #599919 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x invested at 4% \n" ); document.write( "10000-x invested at 5%\r \n" ); document.write( "\n" ); document.write( ".04 x+284=(0.05)(10000-x) \n" ); document.write( "0.04x +284=500-0.05x \n" ); document.write( "0.09x=216 \n" ); document.write( "x=2400 \n" ); document.write( "10000-x=7600\r \n" ); document.write( "\n" ); document.write( "Check 4% of 2400=$96 \n" ); document.write( "5% of 7600=$380\r \n" ); document.write( "\n" ); document.write( "The difference is $284. \n" ); document.write( " |