document.write( "Question 978478: What are the proofs?
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document.write( "(A → B) & (A → C) ├ A→ (B & C) \n" );
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Algebra.Com's Answer #599863 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "That's the law of composition:\r\n" ); document.write( "\r\n" ); document.write( "That's a basic law, so we prove it with a truth table:\r\n" ); document.write( "\r\n" ); document.write( "(A → B) & (A → C) ├ A→ (B & C)\r\n" ); document.write( "\r\n" ); document.write( "Place TTTTFFFF under the A's, TTFFTTFF under the B's and TFTFTFTF under\r\n" ); document.write( "the C's:\r\n" ); document.write( "\r\n" ); document.write( "(A → B) & (A → C) ├ A→ (B & C)\r\n" ); document.write( " T T T T T T T\r\n" ); document.write( " T T T F T T F\r\n" ); document.write( " T F T T T F T\r\n" ); document.write( " T F T F T F F\r\n" ); document.write( " F T F T F T T\r\n" ); document.write( " F T F F F T F\r\n" ); document.write( " F F F T F F T\r\n" ); document.write( " F F F F F F F\r\n" ); document.write( "\r\n" ); document.write( "Under the first → put F only when it has T on the left and F on the\r\n" ); document.write( "right. Otherwise put T. Then you erase what's under the A and the B.\r\n" ); document.write( "\r\n" ); document.write( "(A → B) & (A → C) ├ A→ (B & C)\r\n" ); document.write( " T T T T T T\r\n" ); document.write( " T T F T T F\r\n" ); document.write( " F T T T F T\r\n" ); document.write( " F T F T F F\r\n" ); document.write( " T F T F T T\r\n" ); document.write( " T F F F T F\r\n" ); document.write( " T F T F F T\r\n" ); document.write( " T F F F F F \r\n" ); document.write( " \r\n" ); document.write( "Under the second →, do the same. Put F only when it has T on the left \r\n" ); document.write( "and F on the right. Otherwise put T. Then you erase what's under the \r\n" ); document.write( "A and the C.\r\n" ); document.write( "\r\n" ); document.write( "(A → B) & (A → C) ├ A→ (B & C)\r\n" ); document.write( " T T T T T\r\n" ); document.write( " T F T T F\r\n" ); document.write( " F T T F T\r\n" ); document.write( " F F T F F\r\n" ); document.write( " T T F T T\r\n" ); document.write( " T T F T F\r\n" ); document.write( " T T F F T\r\n" ); document.write( " T T F F F \r\n" ); document.write( "\r\n" ); document.write( "Under the first & put T only when it has T's on both sides of the &, otherwise\r\n" ); document.write( "put F, then erase what's under the first two →'s\r\n" ); document.write( "\r\n" ); document.write( "(A → B) & (A → C) ├ A→ (B & C)\r\n" ); document.write( " T T T T\r\n" ); document.write( " F T T F\r\n" ); document.write( " F T F T\r\n" ); document.write( " F T F F\r\n" ); document.write( " T F T T\r\n" ); document.write( " T F T F\r\n" ); document.write( " T F F T\r\n" ); document.write( " T F F F \r\n" ); document.write( "\r\n" ); document.write( "Under the second & put T only when it has T's on both sides of the &, otherwise\r\n" ); document.write( "put F, then erase what's under the B and C:\r\n" ); document.write( "\r\n" ); document.write( "(A → B) & (A → C) ├ A → (B & C)\r\n" ); document.write( " T T T\r\n" ); document.write( " F T F\r\n" ); document.write( " F T F \r\n" ); document.write( " F T F \r\n" ); document.write( " T F T \r\n" ); document.write( " T F F\r\n" ); document.write( " T F F \r\n" ); document.write( " T F F \r\n" ); document.write( "\r\n" ); document.write( "Under the third →, do the same as before. Put F only when it has T on \r\n" ); document.write( "the left and F on the right. Otherwise put T. Then you erase what's \r\n" ); document.write( "under the A and the (B & C).\r\n" ); document.write( "\r\n" ); document.write( "(A → B) & (A → C) ├ A → (B & C)\r\n" ); document.write( " T T \r\n" ); document.write( " F F \r\n" ); document.write( " F F \r\n" ); document.write( " F F \r\n" ); document.write( " T T \r\n" ); document.write( " T T \r\n" ); document.write( " T T \r\n" ); document.write( " T T \r\n" ); document.write( "\r\n" ); document.write( "Finally under the ├, place T is both sides are the same, and put F\r\n" ); document.write( "otherwise. Then erase the columns on each side of it.\r\n" ); document.write( "\r\n" ); document.write( "(A → B) & (A → C) ├ A → (B & C)\r\n" ); document.write( " T \r\n" ); document.write( " T \r\n" ); document.write( " T \r\n" ); document.write( " T \r\n" ); document.write( " T \r\n" ); document.write( " T \r\n" ); document.write( " T \r\n" ); document.write( " T \r\n" ); document.write( "\r\n" ); document.write( "Since they are all T, the law of composition is proved.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |