document.write( "Question 978452: the width of a rectangle is 3 feet less than its length. if the area of the rectangle is 70 ft2, what are the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #599850 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make the length = 'x' \n" ); document.write( "width = x - 3 \n" ); document.write( "Area = Length x Width \n" ); document.write( "70 = x(x - 3) \n" ); document.write( "70 = x^2 - 3x \n" ); document.write( "Sort into equation ax^2 + bx + c = 0 \n" ); document.write( "x^2 - 3x - 70 = 0 \n" ); document.write( "Factorise \n" ); document.write( "(x + 7)(x - 10)= 0 \n" ); document.write( "x + 7 = 0 \n" ); document.write( "x = -7 (No answer as -ve) \n" ); document.write( "......... \n" ); document.write( "x - 10 = 0 \n" ); document.write( "x = 10 \n" ); document.write( "Length = 10ft \n" ); document.write( "Width = 7ft. \n" ); document.write( "Hope this helps:-) \n" ); document.write( " |