document.write( "Question 978446: Solve the equation for the interval [0,2π)\r
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Algebra.Com's Answer #599843 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"cos%5E2%28x%29%2B2cos%28x%29%2B1\"\"%22%22=%22%22\"\"%220%22\"\r\n" );
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document.write( "Use u-substitution:\r\n" );
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document.write( "Let u = cos(x)\r\n" );
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document.write( "\"u%5E2%2B2u%2B1\"\"%22%22=%22%22\"\"%220%22\"\r\n" );
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document.write( "\"%28u%2B1%29%28u%2B1%29\"\"%22%22=%22%22\"\"%220%22\"\r\n" );
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document.write( "\"%28u%2B1%29%5E2\"\"%22%22=%22%22\"\"%220%22\"\r\n" );
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document.write( "u+1 = 0\r\n" );
document.write( "  u = -1\r\n" );
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document.write( "Substitute cos(x) for u\r\n" );
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document.write( "cos(x) = -1\r\n" );
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document.write( "     x = p\r\n" );
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document.write( "Edwin
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