document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=978314>Question 978314</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thank you for answering my questions :) \r<BR>\n" );
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document.write( "The length of a rectangle is twice its width. If its length is decreased by 3m and its width is increased by 2m, the area of the resulting rectangle is 30m^2. Find the dimension.\r<BR>\n" );
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document.write( "In the previous it said its triangle but its rectangle... And i didnt notice it<BR>\n" );
document.write( "Sorry for the typo error... <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #599751 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=599751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice its width. <BR>\n" );
document.write( "Let width be \"x\"::<BR>\n" );
document.write( "Then length is \"2x\"::<BR>\n" );
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document.write( "If its length is decreased by 3m and its width is increased by 2m, the area of the resulting rectangle is 30m^2. Find the dimension.<BR>\n" );
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document.write( "New length::  2x-3<BR>\n" );
document.write( "New width:: x+2<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "(2x-3)(x+2) = 30<BR>\n" );
document.write( "2x^2 + x - 6 = 30<BR>\n" );
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document.write( "2x^2 + x - 36 = 0<BR>\n" );
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document.write( "(x-4)(2x+9) = 0<BR>\n" );
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document.write( "Positive solution::<BR>\n" );
document.write( "x = 4m (original width)<BR>\n" );
document.write( "2x = 8m (original length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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